语法错误：getter 函数不能有参数

¥Message

SyntaxError: Getter must not have any formal parameters. (V8-based)
SyntaxError: getter functions must have no arguments (Firefox)
SyntaxError: Unexpected identifier 'x'. getter functions must have no parameters. (Safari)

¥Error type

¥What went wrong?

get 属性语法看起来像一个函数，但它更严格，并且并非所有函数语法都允许。getter 总是在没有参数的情况下调用，因此使用任何参数定义它都可能是一个错误。

¥The get property syntax looks like a function, but it is stricter and not all function syntax is allowed. A getter is always invoked with no arguments, so defining it with any parameter is likely an error.

请注意，此错误仅适用于使用 get 语法的属性获取器。如果你使用 Object.defineProperty() 等定义 getter，则 getter 被定义为普通函数，尽管如果 getter 需要任何参数，它仍可能是一个错误，因为它将在没有任何参数的情况下被调用。

¥Note that this error only applies to property getters using the get syntax. If you define the getter using Object.defineProperty(), etc., the getter is defined as a normal function, although it's likely still an error if the getter expects any arguments, as it will be called without any.

¥Examples

¥Invalid cases

const obj = {
  get value(type) {
    return type === "string" ? String(Math.random()) : Math.random();
  },
};

¥Valid cases

// Remove the parameter
const obj = {
  get value() {
    return Math.random();
  },
};

// Use a normal method, if you need a parameter
const obj = {
  getValue(type) {
    return type === "string" ? String(Math.random()) : Math.random();
  },
};

¥See also

• 函数
• get