按位非 (~)
按位 NOT (~
) 运算符返回一个数字或 BigInt,其二进制表示形式在每个位位置都有 1
,操作数的相应位为 0
,否则为 0
。
¥The bitwise NOT (~
) operator returns a number or BigInt whose binary representation has a 1
in each bit position for which the corresponding bit of the operand is 0
, and a 0
otherwise.
Try it
语法
描述
¥Description
~
运算符针对两种类型的操作数进行重载:编号和 BigInt。对于数字,该运算符返回一个 32 位整数。对于 BigInts,该运算符返回一个 BigInt。它首先 将操作数强制为数值 并测试它的类型。如果操作数变为 BigInt,则执行 BigInt NOT;否则,它将操作数转换为 32 位整数 并执行数字按位 NOT。
¥The ~
operator is overloaded for two types of operands: number and BigInt. For numbers, the operator returns a 32-bit integer. For BigInts, the operator returns a BigInt. It first coerces the operand to a numeric value and tests the type of it. It performs BigInt NOT if the operand becomes a BigInt; otherwise, it converts the operand to a 32-bit integer and performs number bitwise NOT.
该运算符对 二进制补码 中操作数的位表示进行运算。该运算符应用于每一位,并按位构造结果。
¥The operator operates on the operands' bit representations in two's complement. The operator is applied to each bit, and the result is constructed bitwise.
NOT 运算的真值表为:
¥The truth table for the NOT operation is:
x | 不是 x |
---|---|
0 | 1 |
1 | 0 |
9 (base 10) = 00000000000000000000000000001001 (base 2) -------------------------------- ~9 (base 10) = 11111111111111111111111111110110 (base 2) = -10 (base 10)
超过 32 位的数字将丢弃其最高有效位。例如,以下超过 32 位的整数将被转换为 32 位整数:
¥Numbers with more than 32 bits get their most significant bits discarded. For example, the following integer with more than 32 bits will be converted to a 32-bit integer:
Before: 11100110111110100000000000000110000000000001 After: 10100000000000000110000000000001
对于 BigInts,没有截断。从概念上讲,将正 BigInt 理解为具有无限数量的前导 0
位,将负 BigInt 理解为具有无限数量的前导 1
位。
¥For BigInts, there's no truncation. Conceptually, understand positive BigInts as having an infinite number of leading 0
bits, and negative BigInts having an infinite number of leading 1
bits.
按位对任何 32 位整数 x
进行 NOT 运算会得到 -(x + 1)
。例如,~-5
产生 4
。
¥Bitwise NOTing any 32-bit integer x
yields -(x + 1)
. For example, ~-5
yields 4
.
对任意数字 x
进行按位取反两次会返回转换为 32 位整数的 x
。不要使用 ~~x
将数字截断为整数;使用 Math.trunc()
代替。由于数字使用 32 位表示,~-1
和 ~4294967295
(232 - 1) 都会生成 0
。
¥Bitwise NOTing any number x
twice returns x
converted to a 32-bit integer. Do not use ~~x
to truncate numbers to integers; use Math.trunc()
instead. Due to using 32-bit representation for numbers, both ~-1
and ~4294967295
(232 - 1) result in 0
.
示例
使用按位 NOT
规范
Specification |
---|
ECMAScript Language Specification # sec-bitwise-not-operator |
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¥See also